A block is lying on the horizontal frictionless surface. One end of a uniform rope is fixed to the block which is pulled in the horizontal direction by applying a force F at the other end. If the mass of the rope is half the mass of the block, the tension in the middle of the rope will be

Question

Infinity Learn · Accepted Answer

The acceleration of $$block-rope$$ $$systema=F(M+m)where$$ M $$=$$ mass of block and m $$=mass$$ of rope So, the tension in the middle of the rope will be $$T={M+(m/2)}$$ $$a=M+(m/2)F(M+m)Given$$ that m $$=$$ $$M/2$$∴$$T=M+(M/4)M+(M/2)F=5F6$$

A block is lying on the horizontal frictionless surface. One end of a uniform rope is fixed to the block which is pulled in the horizontal direction by applying a force F at the other end. If the mass of the rope is half the mass of the block, the tension in the middle of the rope will be

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material