Q.

A block m slides down a curved frictionless track, starting from rest. The curve obeys the equation y=x22.  The tangential acceleration of the block is

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a

g

b

gxx2+4

c

g2

d

gxx2+1

answer is D.

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Detailed Solution

dydx=tan⁡θ=x⇒sin⁡θ=xx2+1Tangential acceleration =gsin⁡θ=gxx2+1
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A block m slides down a curved frictionless track, starting from rest. The curve obeys the equation y=x22.  The tangential acceleration of the block is