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Q.

A block of m is suspended by a spring and deflection of the spring is found to be A. Now the block is pulled downward by a distance A and released. Then energy of oscillation the block is

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a

14mgA

b

2 mgA

c

12 mgA

d

mgA

answer is C.

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Detailed Solution

When the block is in equilibrium mg = KAAfter release the block will oscillate with amplitude A. Angular frequency of the block, w=kmEnergy of oscillation =12mw2A2=12mkmA2=12kA2=12mgA
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