A block of mass 100 g attached to a spring of spring constant 100 Nm-1 is lying on a frictionless floor as shown in the figure. The block is moved to compress the spring by 10 cm and then released. If the collisions with the wall in front are elastic, then the time period of the motion is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
0.2 s
b
0.1 s
c
0.15 s
d
0.132 s
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
T=2πmk=2π0.1100=0.198 sFrom x = A sin ωt or 5=10 sin ωt⇒ ωt=π6 or 2πTt=π6 or 2t=T6The desired time in the question will be T2+ 2tor T2+T6=2T3=23(0.198)=0.132 s