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A block of mass 100 g attached to a spring of spring constant 100 Nm-1 is lying on a frictionless floor as shown in the figure. The block is moved to compress the spring by 10 cm and then released. If the collisions with the wall in front are elastic, then the time period of the motion is

a
0.2 s
b
0.1 s
c
0.15 s
d
0.132 s

detailed solution

Correct option is D

T=2πmk=2π0.1100=0.198 sFrom x = A sin ωt or 5=10 sin ωt⇒    ωt=π6  or  2πTt=π6   or   2t=T6The desired time in the question will be T2+ 2tor                    T2+T6=2T3=23(0.198)=0.132 s

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