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Q.

A block A of mass 3kg and another block B of mass 2 kg are connected by a light inextensible string as shown in figure. If the coefficient of friction between the surface of the table and A is 0.5. What minimum mass C should be placed on A so that the system is  in equilibrium? (g=10m/s2)

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a

3kg

b

2kg

c

1kg

d

4kg

answer is C.

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Detailed Solution

mBg=mA+mCgμ2×10=3+mC12×10mC=1kg
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