A block of mass 2Kg is attached to the lower end of a spring of force constant 1960 Nm−1 hanging from rigid support. Initially spring is unstretched, if the block is suddenly released the maximum elongation produced in spring is

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1cm

2cm

2.2cm

3cm

answer is B.

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Detailed Solution

Loos of P.E= gain of elastic potential energymgx=12kx2 x=2mgk=2×2×9.81960=2100m x=2cm

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