First slide

Conservation of mechanical energy

Question

A block of mass 2Kg is attached to the lower end of a spring of force constant 1960 $N m^{- 1}$ hanging from rigid support. Initially spring is unstretched, if the block is suddenly released the maximum elongation produced in spring is

Moderate

A

1cm
B

2cm
C

2.2cm
D

3cm

Solution

Loos of P.E= gain of elastic potential energy
$\begin{array}{l} mg x = \frac{1}{2} k x^{2} \\ x = \frac{2 mg}{k} = \frac{2 \times 2 \times 9.8}{1960} = \frac{2}{100} m \\ x = 2 cm \end{array}$

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