A block of mass $$0$$ . $$5$$ kg has an initial velocity of $$10$$ $$m/s$$ down an inclined rough plane of angle $$300$$ as shown in fig. (6). The coefficient of friction between the block and inclined surface being $$0$$ $$2$$. The velocity of the block after it travels a distance of $$10$$ m is

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Infinity Learn · Accepted Answer

The acceleration is given $$bya=gsin$$⁡$$30$$∘−μ$$cos$$⁡$$30$$∘ $$=9$$⋅$$812$$−$$0$$⋅$$2$$×$$32=9$$⋅$$8$$×(0$$⋅$$3268) $$=3$$⋅$$2m/s2$$  Now $$v2=u2+2as$$ $$v2=(10)2+2$$×$$3$$⋅$$2$$×$$10=164$$ v≈$$13m/s$$

A block of mass 0 . 5 kg has an initial velocity of 10 m/s down an inclined rough plane of angle 30⁰ as shown in fig. (6). The coefficient of friction between the block and inclined surface being 0 2. The velocity of the block after it travels a distance of 10 m is

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A block of mass 0 . 5 kg has an initial velocity of 10 m/s down an inclined rough plane of angle 300 as shown in fig. (6). The coefficient of friction between the block and inclined surface being 0 2. The velocity of the block after it travels a distance of 10 m is

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A block of mass 0 . 5 kg has an initial velocity of 10 m/s down an inclined rough plane of angle 30⁰ as shown in fig. (6). The coefficient of friction between the block and inclined surface being 0 2. The velocity of the block after it travels a distance of 10 m is