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A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.4, the magnitude of the frictional force acting on the block is 

a
2.5 N
b
0.98 N
c
4.9 N
d
0.49 N

detailed solution

Correct option is B

Limiting friction Fl=μsR=0.4×(5)=2.0 NSince downward force is less than limiting friction therefore block is at rest so the static force of friction will work on it.Fs= downward force = Weight=0.1×9.8=0.98 N

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