A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.4, the magnitude of the frictional force acting on the block is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2.5 N
b
0.98 N
c
4.9 N
d
0.49 N
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Limiting friction Fl=μsR=0.4×(5)=2.0 NSince downward force is less than limiting friction therefore block is at rest so the static force of friction will work on it.Fs= downward force = Weight=0.1×9.8=0.98 N