A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.4, the magnitude of the frictional force acting on the block is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
2.5 N
b
0.98 N
c
4.9 N
d
0.49 N
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Limiting friction Fl=μsR=0.4×(5)=2.0 NSince downward force is less than limiting friction therefore block is at rest so the static force of friction will work on it.Fs= downward force = Weight=0.1×9.8=0.98 N
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
A block of mass 0.1 kg is held against a wall by applying a horizontal force of 5 N on the block. If the coefficient of friction between the block and the wall is 0.4, the magnitude of the frictional force acting on the block is