A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4 If a force F of 2.5 N is applied on the block as shown in fig. the frictional force between the block and the floor will be

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2.5 N

5 N

7.84 N

10 N

answer is A.

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Detailed Solution

The limiting friction is given byμR=μ×mg=0⋅4×2×9⋅8=7⋅84NAs the applied force (2.5 N) is less than the limiting friction, therefore in this case, the friction should be equal to 2.5N itself.

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