A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 N is applied on the block as shown in the figure, the frictional force between the block and the floor will be

Applied force = 2.5 NLimiting friction = μmg = 0.4 x 2 x  9.8 = 7.84 NFor the given condition applied force is  less than limiting friction..'. Static friction on a body = Applied force                                           = 2.5 N