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A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 N is applied on the block as shown in the figure, the frictional force between the block and the floor will be

a
2.5 N
b
5 N
c
7.84 N
d
10 N

detailed solution

Correct option is A

Applied force = 2.5 NLimiting friction = μmg = 0.4 x 2 x  9.8 = 7.84 NFor the given condition applied force is  less than limiting friction..'. Static friction on a body = Applied force                                           = 2.5 N

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