A block of mass 2 kg is kept on a rough inclined plane making an angle of 300 with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is

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10 N

73 N

10 × 3 N

7 N

answer is A.

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Detailed Solution

Since the block is at rest, therefore force of friction= mg sinθ = 2 ×10×sin 300 = 10 N

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