A block of mass 0.50kg is moving with a speed of 2.00ms−1  on a smooth surface. It strikes another mass of 1.00 kg and then they move together as a single body. The energy loss during the collision is

Initial kinetic energy of the system K.Ei=12mu2+12M(0)2=12×0.5×2×2+0=1J For collision, applying conservation of linear momentumm×u=(m+M)×v ∴0.5×2=(0.5+1)×v ⇒v=23m/s Final kinetic energy of the system is K.Ef=12(m+M)v2=12(0.5+1)×23×23=13J ∴  Energy loss during collision = (1−13)J=0.67J