A block of mass 5 kg is moving in x-direction with a constant speed of 10 m/s. it is subjected to a retarding force F=−0.2x Nduring its travel from x=20 m to x=30 m. its final kinetic energy will be

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answer is 3.

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Detailed Solution

According to Work-Energy theoremKf−Ki=WKf=Ki+W =12×5×102+∫2030−0.2xdx =200 J

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