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Q.

A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s2(g=10ms−2). The force of friction between lorry and block is

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a

48N

b

24N

c

40N

d

zero

answer is C.

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Detailed Solution

fs =μSma=0.8×4×15=48Nmg=4×10=40N as mg
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A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s2(g=10ms−2). The force of friction between lorry and block is