A block of mass $$4kg$$ is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is $$0.8$$. The lorry is moving with an acceleration of $$15$$ $$m/s2$$ (g$$ $$=$$ $$10ms-2). The force of friction between lorry and block is

Question

A block of mass $$4kg$$ is placed in contact with  the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is $$0.8$$. The lorry is moving with an acceleration of $$15$$ $$m/s2$$ (g$$ $$=$$ $$10ms-2). The force of friction between lorry and block is

Infinity Learn · Accepted Answer

fs $$=$$ µsma $$=$$ $$0.8$$ x $$4$$ x $$15$$ $$=$$ $$48Nmg$$ $$=$$ $$4$$ x $$10$$ $$=$$ $$40N$$  as mg < fsfriction $$=$$ mg $$=$$ $$40$$ N

A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s² (g = 10ms^-2). The force of friction between lorry and block is

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A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s2 (g = 10ms-2). The force of friction between lorry and block is

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A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s² (g = 10ms^-2). The force of friction between lorry and block is