First slide

Static friction

Question

A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8. The lorry is moving with an acceleration of 15 m/s² (g = 10ms^-2). The force of friction between lorry and block is

Moderate

A

48N
B

24N
C

40N
D

zero

Solution

f_s = µ_sma = 0.8 x 4 x 15 = 48N
mg = 4 x 10 = 40N as mg < f_s
friction = mg = 40 N

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