First slide

Two block problem

Question

Block A of mass 2 kg is placed over a block B of mass 8 kg. The combination is placed on a rough horizontal surface. If g = l0 ${ms}^{- 2}$ , coefficient of friction between B and floor = 0.5, , coefficient of friction between A and B = 0.4 and a horizontal force of 10 N is applied on 8 kg block, then the force of friction between A and B is

Moderate

A

100 N
B

50 N
C

40 N
D

None of these

Solution

f= $μ$ R = $μ$ mg |m is mass of the combination]
f = 0.5 x l0x l0N = 50N
So, a force of 10 N is unable to start the motion of the system. Therefore block A has no tendency to move over block B. So frictional force between A and B is zero .

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