First slide

Friction

Question

A block of mass 4kg is pressed against a wall by two perpendicular horizontal forces as shown in the figure. $F_{1}$ is perpendicular to the wall and $F_{2}$ is parallel to the wall. $μ_{s} = 0.8$ , $μ_{k} = 0.5$ and $g = 10 m / s^{2}$
For $F_{1} = 75 N$ and $F_{2} = 30 N$ , the block remains at rest on the wall then the force of friction is

Moderate

A

30 N
B

40 N
C

50 N
D

45 N

Solution

Given mass of block $m = 4 kg$
$μ_{s} = 0.8$ ; $μ_{k} = 0.5$ and $g = 10 m / s^{2}$
Limiting value of static friction is $f_{L} = μ_{S} N = 0.8 \times 75 = 60 N$ ,
whereas resultant of forces on the plane of the wall i.e. weight $= 40 N$ and $F_{2} = 30 N$ is $50 N$ . Hence friction will adjust its value at $50 N$ .

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