A block of mass 4kg is pressed against a wall by two perpendicular horizontal forces as shown in the figure. F1 is perpendicular to the wall and F2 is parallel to the wall. μs=0.8 , μk=0.5 and g=10 m/s2For F1=75 N and F2=30 N, the block remains at rest on the wall then the force of friction is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
30 N
b
40 N
c
50 N
d
45 N
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given mass of block m=4 kgμs=0.8 ; μk=0.5 and g=10 m/s2 Limiting value of static friction is fL=μSN=0.8×75= 60 N, whereas resultant of forces on the plane of the wall i.e. weight =40 N and F2=30 N is 50 N . Hence friction will adjust its value at 50 N.
A block of mass 4kg is pressed against a wall by two perpendicular horizontal forces as shown in the figure. F1 is perpendicular to the wall and F2 is parallel to the wall. μs=0.8 , μk=0.5 and g=10 m/s2For F1=75 N and F2=30 N, the block remains at rest on the wall then the force of friction is