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Q.

A block of mass 100kg is pulled up on an inclined plane of length 10m and 3m high by a constant force of 400N. If the work done against friction is 200J, the velocity of the block at the top of the inclined plane is (g = 10ms−2 )

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a

2ms−1

b

4ms−1

c

8ms−1

d

1ms−1

answer is B.

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Detailed Solution

F.S=mgh+f.S+12mv2 400×10=100×10×3+200+12×100×v2⇒V=4ms
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