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Q.

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 30° by a force of 10 N parallel to the inclined surface as shown in the figure. The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline, then the work against gravity is (Take g = 10 m s-2)

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a

10 J

b

50 J

c

100 J

d

150 J

answer is B.

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Detailed Solution

The various forces acting on the block are as shown in the figure. Here, m=1kg,θ=30∘,F=10Nμ=0.1,d=10mWork done against gravity is   Wg=mgdsin⁡θ        =(1kg)×10ms−2×10m×sin⁡30∘=50J
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