First slide

Work

Question

A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of 30° by a force of 10 N parallel to the inclined surface as shown in the figure. The coefficient of friction between block and the incline is 0.1. If the block is pushed up by 10 m along the incline, then the work against gravity is (Take g = 10 m s^-2)

Easy

A

10 J
B

50 J
C

100 J
D

150 J

Solution

The various forces acting on the block are as shown in the figure.

Here, ${m=1kg,θ=30}^{\circ}, F = 10 N$
$μ = 0 .1, d = 10 m$
Work done against gravity is
$W_{g} = mgdsin θ$
$= (1 kg) \times (10 {ms}^{- 2}) \times 10 m \times \sin 30^{\circ} = 50 J$

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