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A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.50. If g = 10 m/s2, then the magnitude of a force acting upwards at an angle of 60° from the horizontal that will just start the block moving is

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a

5N

b

5.36 N

c

74.6 N

d

10 N

answer is B.

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Detailed Solution

R+Psin⁡60∘=mgorR=mg−Psin⁡60∘Now, frictional force, f=μR∴ f=μ[mg−Psin⁡60∘] ...(1)For the body to just movePcos⁡60∘=f=μmg−Psin⁡60∘∴P2=0⋅51×10−P22 or P=10−P32 or P+P32=10 or P=5⋅36N.

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A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.50. If g = 10 m/s2, then the magnitude of a force acting upwards at an angle of 60° from the horizontal that will just start the block moving is