A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. The magnitude of the force acting upwards at an angle of 60° from the horizontal that will just start the block moving is
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a
5 N
b
202+3N
c
202-3N
d
10 N
answer is B.
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Detailed Solution
R + F sin 600 = mgR = mg - 3F2If block just starts movingF cos 600 = fmax= μRor F + 3F2 = 10 or F = 202+3