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A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and the surface is 0.5. Tension in the cord is (Take, g = 9.8 ms-2)

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a

49 N

b

zero

c

36.75 N

d

12.75 N

answer is C.

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Detailed Solution

⇒ T-f = 5a, T-μmg = 5aT-0.5×5×9.8 = 5a ......(i)⇒ 5g - T = 5a ......(ii)From Eqs. (i) and (ii), we get5×9.8-0.5×5×9.8=10a⇒ 0.5×5×9.8=10a⇒ a=2.45 m/s2From Eq (ii), we get5×9.8-5×2.45=T⇒ T=36.75 N

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A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and the surface is 0.5. Tension in the cord is (Take, g = 9.8 ms-2)