First slide

Friction on horizontal surface

Question

A block of mass 5 kg resting on a horizontal surface is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and the surface is 0.5. Tension in the cord is (Take, g = 9.8 ms^-2)

Moderate

A

49 N
B

zero
C

36.75 N
D

12.75 N

Solution

$\Rightarrow T - f = 5 a, T - μ m g = 5 a$
$T - 0.5 \times 5 \times 9.8 = 5 a . . . . . . (i)$
$\Rightarrow 5 g - T = 5 a . . . . . . (ii)$
From Eqs. (i) and (ii), we get
$5 \times 9.8 - 0.5 \times 5 \times 9.8 = 10 a$
$\Rightarrow 0.5 \times 5 \times 9.8 = 10 a$
$\Rightarrow a = 2.45 m / s^{2}$
From Eq (ii), we get
$5 \times 9.8 - 5 \times 2.45 = T$
$\Rightarrow T = 36.75 N$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App