Q.

A block of mass 4 kg rests on a horizontal surface. A vertically upward force of 52 N is applied on the block. If g=10  m/s2, the work done by the applied force in 2 S is

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a

264 J

b

312 J

c

150 J

d

58 J

answer is B.

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Detailed Solution

(2)Acceleration of the block,a=52−4  × 104 m/s2=3  m/s2At t = 2 sec, distance covered = h =12 ×  3×22 m=6m∴   Work done by 52 N force, W = 52 x 6 J = 312 Joule
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