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A block of mass 4 kg rests on a horizontal surface. A vertically upward force of 52 N is applied on the block. If g=10  m/s2, the work done by the applied force in 2 S is

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a
264 J
b
312 J
c
150 J
d
58 J

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detailed solution

Correct option is B

(2)Acceleration of the block,a=52−4  × 104 m/s2=3  m/s2At t = 2 sec, distance covered = h =12 ×  3×22 m=6m∴   Work done by 52 N force, W = 52 x 6 J = 312 Joule

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Similar Questions

The curved portions are smooth and horizontal surface is rough. The block is released from P. At what distance from A, it will stop (if μ = 0.8)?

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