First slide

Work Energy Theorem

Question

A block of mass 4 kg rests on a horizontal surface. A vertically upward force of 52 N is applied on the block. If $g = 10 m / s^{2},$ the work done by the applied force in 2 S is

Easy

A

264 J
B

312 J
C

150 J
D

58 J

Solution

(2)
Acceleration of the block,
$a = \frac{52 - 4 \times 10}{4} m / s^{2} = 3 m / s^{2}$
At t = 2 sec, distance covered = h $= \frac{1}{2} \times 3 \times 2^{2} m = 6 m$
$∴$ Work done by 52 N force, W = 52 x 6 J = 312 Joule

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