Q.

A block of mass 15 kg rests on a rough horizontal surface having coefficient of friction 0.6 between the block and the surface. A machine, delivering a constant power of 900 watt starts moving the block on the surface. Then maximum velocity of the block is

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a

3 m/s

b

1.5 m/s

c

6 m/s

d

10 m/s

answer is D.

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Detailed Solution

Velocity of the block gradually increases and finally it becomes constant. Vmax and at that time the entire power output of the machine is used by the block in overcoming the friction. ∴ μmg.Vmax=P⇒ Vmax=Pμmg=9000.6×15×10m/s=10 ms-1
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A block of mass 15 kg rests on a rough horizontal surface having coefficient of friction 0.6 between the block and the surface. A machine, delivering a constant power of 900 watt starts moving the block on the surface. Then maximum velocity of the block is