A block of mass 15 kg rests on a rough horizontal surface having coefficient of friction 0.6 between the block and the surface. A machine, delivering a constant power of 900 watt starts moving the block on the surface. Then maximum velocity of the block is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
3 m/s
b
1.5 m/s
c
6 m/s
d
10 m/s
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Velocity of the block gradually increases and finally it becomes constant. Vmax and at that time the entire power output of the machine is used by the block in overcoming the friction. ∴ μmg.Vmax=P⇒ Vmax=Pμmg=9000.6×15×10m/s=10 ms-1