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Q.

A block of mass 4 kg rests on rough horizontal surface. A vertically downward force P is applied on the block. The block just starts sliding when horizontal force P is applied on the block. If P=12mg, find the coefficient of friction between the block and the surface.

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a

3/4

b

1/2

c

2/3

d

1/3

answer is C.

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Detailed Solution

Normal reaction N = mg + P∴ fmax=μN=μmg+P∴ P=μmg+P⇒μ=12mgmg+p=12mgmg+12mg=13

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A block of mass 4 kg rests on rough horizontal surface. A vertically downward force P is applied on the block. The block just starts sliding when horizontal force P is applied on the block. If P=12mg, find the coefficient of friction between the block and the surface.