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A block of mass 4 kg rests on rough horizontal surface. A vertically downward force P is applied on the block. The block just starts sliding when horizontal force P is applied on the block. If P=12mg, find the coefficient of friction between the block and the surface.

a
3/4
b
1/2
c
2/3
d
1/3

detailed solution

Correct option is C

Normal reaction N = mg + P∴  fmax=μN=μmg+P∴  P=μmg+P⇒μ=12mgmg+p=12mgmg+12mg=13

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