Questions
A block of mass 2 kg rests on a rough inclined plane making an angle of 30° with the horizontal. The coefficient of static friction between the block and the plane is 0.7. The frictional force on the block is
detailed solution
Correct option is A
Angle of friction φ = tan-10.7 >300 . Therefore the block will be in eqilibrium .The actual frictional force will be equal to mgsinθ=2×9⋅8×12=9⋅8N.Talk to our academic expert!
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