First slide

Static friction

Question

A block of mass 2 kg rests on a rough inclined plane making an angle of $30^{0}$ with the horizontal. If $μ_{s}$ = 0.6 , what is the frictional force on the block ?

Moderate

A

9.8N
B

19.6N
C

14.7N
D

4.9N

Solution

$f_{s} = μ_{s} m g \cos θ = 0.6 \times 2 \times 9.8 \times \frac{\sqrt{3}}{2}$
$0.6 \times 9.8 \times \sqrt{3}$
$m g \sin θ = 2 \times 9.8 \times \frac{1}{2} = 9.8$
$f_{s} > m g \sin θ$
friction = mgsinθ = 9.8N

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