Questions
A block of mass 2 kg slides down a curved track that is one quarter of a circle of radius 1 m [see fig. (1)]. Its speed at the bottom is 4 m,/s. Work done by frictional force is (take g = 10 m / s2 )
detailed solution
Correct option is A
In absence of friction, the velocity at the bottom of quarter circleV=2gR K.E. =12mv2=mgR=2×10×1=20J Actual K.E. =12×2×(4)2=16J Work done by frictional force = decrease in K E. =16J−20J=−4JSimilar Questions
The curved portions are smooth and horizontal surface is rough. The block is released from P. At what distance from A, it will stop (if = 0.8)?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests