A block of mass $$2$$ kg slides down a curved track that is one quarter of a circle of radius $$1$$ m [see fig. (1)]. Its speed at the bottom is $$4$$ m,$$/s$$. Work done by frictional force is (take$$ g $$=$$ $$10$$ m $$/$$ $$s2$$ $$)

Question

Infinity Learn · Accepted Answer

In absence of friction, the velocity at the bottom of quarter $$circleV=2gR$$  K.E. $$=12mv2=mgR=2$$×$$10$$×$$1=20J$$  Actual K.E. $$=12$$×$$2$$×$$(4)2=16J$$ Work done by frictional force $$=$$ decrease in K E. $$=16J$$−$$20J=$$−$$4J$$

A block of mass 2 kg slides down a curved track that is one quarter of a circle of radius 1 m [see fig. (1)]. Its speed at the bottom is 4 m,/s. Work done by frictional force is (take g = 10 m / s2 )

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