First slide

Work done by Diff type of forces

Question

A block of mass 1 kg slides down a rough inclined plane of inclination 60⁰ starting from its top. If coefficient of kinetic friction is 0.5 and length of the plane d = 2 m, then work done against friction is

Moderate

A

2.45 J
B

4.9 J
C

9.8 J
D

19.6 J

Solution

Work done against friction $= (μ m g \cos θ) d$
$= 0.5 \times 1 \times 9.8 \times \cos 60 ° \times 2 = 4.9 J$

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