A block of mass 1 kg slides down a rough inclined plane of inclination 600 starting from its top. If coefficient of kinetic friction is 0.5 and length of the plane d = 2 m, then work done against friction is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

2.45 J

4.9 J

9.8 J

19.6 J

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Work done against friction =(μmgcosθ)d=0.5×1×9.8×cos60°×2=4.9 J