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A block of mass 1 kg slides down a rough inclined plane of inclination 600 starting from its top. If coefficient of kinetic friction is 0.5 and length of the plane d = 2 m, then work done against friction is

a
2.45 J
b
4.9 J
c
9.8 J
d
19.6 J

detailed solution

Correct option is B

Work done against friction  =(μmgcosθ)d=0.5×1×9.8×cos60°×2=4.9 J

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