Questions
A block of mass 5 kg slides down a rough inclined surface. The angle of inclination is 450. The
coefficient of sliding friction is 0.20 . When the block slides 10 cm, the work done on the block by
force of friction is
detailed solution
Correct option is A
Work done by frictional force, Wf=fscos180°=(μmgcosθ)(-1)(s)=-0.20×5×10×12×0.1 ∵θ=45°=-12 JTalk to our academic expert!
Similar Questions
Two blocks of mass M and m are connected with a string which passes over a smooth pulley as shown in fig. The mass M is placed on a rough
inclined plane. The coefficient of friction between the block and the inclined plane is µ. What should be the minimum mass m so that the block M slides upward ?
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
