A block of mass 2 kg is sliding down a rough inclined plane having inclination 30° with constant velocity of 0.5 m/s. Then coefficient of kinetic friction between the block and the same is
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a
0.577
b
0.672
c
0.425
d
0.867
answer is A.
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Detailed Solution
Since velocity of the block is constant,mgsin θ−fk=0⇒mgsin θ−μkmgcosθ=0 μk=tan θ ∴μk=tan 30∘=13=0.577