A block of mass 2 kg is sliding down a rough inclined plane having inclination 30° with constant velocity of 0.5 m/s. Then coefficient of kinetic friction between the block and the same is

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0.577

0.672

0.425

0.867

answer is A.

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Detailed Solution

Since velocity of the block is constant,mgsin⁡ θ−fk=0⇒mgsin θ−μkmgcosθ=0 μk=tan ⁡θ ∴μk=tan ⁡30∘=13=0.577

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