A block of mass 2 kg is sliding down a rough inclined plane having inclination 300 with constant velocity of 0.5 m/s. Then coefficient of kinetic friction between the block and the same is
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a
0.577
b
0.672
c
0.425
d
0.867
answer is A.
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Detailed Solution
(1)Since velocity of the block is constant,mgsinθ−fk=0 ⇒ mgsinθ −μk.mgcosθ=0 ⇒ μk=tanθ∴ μk=tan300=13 =0.577.