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A block of mass 2 kg is sliding down a rough inclined plane having inclination 300 with constant velocity of 0.5 m/s. Then coefficient of kinetic friction between the block and the same is

a
0.577
b
0.672
c
0.425
d
0.867

detailed solution

Correct option is A

(1)Since velocity of the block is constant,mgsinθ−fk=0  ⇒  mgsinθ  −μk.mgcosθ=0  ⇒  μk=tanθ∴     μk=tan300=13  =0.577.

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