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Q.

A block of mass 50 kgk is suspended by two strings 1 and 2 as shown in figure. The strings are of same length. Cross sectional area and young's modulus of the string 1 are A and Y and those of string 2 are 2A and 2Y respectively. If the block always remains horizontal, tension induced in string 1 is

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a

100 N

b

250 N

c

200 N

d

300 N

answer is A.

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Detailed Solution

Elongation produced in 1 = Elongation produced in 2⇒T1.lA1.Y1=T2.lA2l2⇒T1T2=A1A2.Y1Y2=12.12⇒T1T2=14........1Also, T1+T2=500 N.........2Solving, T1=100 N
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