A block of mass m is attached to two unstretched springs of spring constants k, each as shown. The block is displaced towards right through a distance x and is released. The speed of the block as it passes through the mean position will be

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xm2k

x2km

xmk

x2km

answer is B.

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Detailed Solution

Total PE of spring = Total KE of block12kx2+12kx2=12mv2⇒kx2=12mv2⇒ Speed of the block, v=x2km

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