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Q.

A block of mass m at the end of a string is whirled round in a vertical circle of radius R. The critical speed of the block at the top of its swing below which the string would slacken before the block reaches the top is

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a

R g

b

(Rg)2

c

R/g

d

Rg

answer is D.

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Detailed Solution

Centripetal acceleration = acceleration due to gravity v2R=g   or   v=Rg
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A block of mass m at the end of a string is whirled round in a vertical circle of radius R. The critical speed of the block at the top of its swing below which the string would slacken before the block reaches the top is