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Q.

Block A of mass M in the figure is released from rest when the extension in the spring is x0. The maximum downward displacement of the block is (assume x0< Mgk)

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a

2(Mgk-x0)

b

Mg2k+x0

c

2Mgk-x0

d

2Mgk+x0

answer is A.

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Detailed Solution

Loss in gravitational potential energy of block is equal to gain in elastic potential energy of springMgx = 12k(x+x0)2-12kx02On solving x = 2(Mgk-x0)

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Block A of mass M in the figure is released from rest when the extension in the spring is x0. The maximum downward displacement of the block is (assume x0< Mgk)