First slide
Potential energy
Question

Block A of mass M in the figure is released from rest when the extension in the spring is x0. The maximum downward displacement of the block is (assume x0< Mgk)

Easy
Solution

Loss in gravitational potential energy of block is equal to gain in elastic potential energy of spring

Mgx = 12k(x+x0)2-12kx02

On solving x = 2(Mgk-x0)

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App