First slide
Friction on inclined plane of angle more than angle of repose
Question

A block of mass m is kept on an inclined plane of a lift moving down with acceleration of 2 ms-2. What should be the coefficient of friction to let the block move down with constant velocity relative to lift?

Moderate
Solution

m(g-a)sinθ=μm(g-a)cosθ

  μ=tanθ=tan30°=13

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