A block of mass m = 11. 7 kg is to be pushed a distance of s = 4.65 m along an incline and raised to a distance of h = 2.86 m. Assuming frictionless surface, calculate the work done in applying a force parallel to the incline to push the block up at a constant speed. (Take, g = 9.8 ms-2)
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
328 J
b
656J
c
164 J
d
530 J
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Given, m=11.7 kg,s=4.65 m,h=2.86 mFrom the figure, sinθ=hs=2.864.65=0.615Also, component of mg along the incline is mg sin θ.∴Work done by this force = mg sin θ· s= 11.7 x 9.8 x 0.615 x 4.65= 11.7 x 9.8 x 2.86 = 327.9 ≃ 328J