Questions
A block of mass M = 5 kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2. When a force F = 40 N is applied, the acceleration of the block will be (g = 10 ms2)
detailed solution
Correct option is A
Kinetic friction μkR=0.2mg−Fsin 30∘=0.25×10−40×12=0.2(50−20)=6N Acceleration of the block = Fcos 30∘− Kinetic friction Mass =40×32−65=5.73m/s2.Talk to our academic expert!
Similar Questions
A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. The magnitude of the force acting upwards at an angle of 60° from the horizontal that will just start the block moving is
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