Questions
A block of mass m = 5 kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2. When a force F = 40 N is applied, the acceleration of the block will be (g = 10 )
detailed solution
Correct option is A
Kinetic friction = μkR = 0.2(mg - F sin 300)= 0.2 (5×10-40×12) = 0.2 (50-20) = 6 NAcceleration of the block= F cos 300-Kinetic frictionMass= 40 ×32-65 = 5.73 m/s2Talk to our academic expert!
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A block of mass 1 kg is at rest on a horizontal table. The coefficient of static friction between the block and the table is 0.5. The magnitude of the force acting upwards at an angle of 60° from the horizontal that will just start the block moving is
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