First slide

Work done by Diff type of forces

Question

A block of mass 'M' is lowered with the help of a rope of negligible mass through a distance 'd' with an acceleration of g/3 . Work done by the rope on the block is

Moderate

A

$\frac{2 m g d}{3}$
B

$- \frac{2 m g d}{3}$
C

$\frac{m g d}{3}$
D

$- \frac{m g d}{3}$

Solution

Tension in the rope
T = Mg - Mg/3 = (2/3) mg
.: W = $\overset{⇀}{T} . \overset{⇀}{S}$ = TS cos 18 $0^{0}$
= $\frac{2 m g d}{3} (- 1)$

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