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A block of mass m is lying on a another block of mass M, lying on a horizontal frictionless surface as shown in Figure. If the coefficient static friction between the two blocks is μs , the minimum horizontal force F that must be applied to block of mass m so that it moves over block of mass M is

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a

zero

b

mg

c

mg/μs

d

μsmg(1+mM)

answer is D.

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Detailed Solution

When block m is on the verge of moving on block M , acceleration of the upper block au=F-μmgm. At that instant acceleration of the lower block , aL=μmgM. But au=aL . Solving , F = μmg (1+ mM)

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A block of mass m is lying on a another block of mass M, lying on a horizontal frictionless surface as shown in Figure. If the coefficient static friction between the two blocks is μs , the minimum horizontal force F that must be applied to block of mass m so that it moves over block of mass M is