A block of mass m, lying on a horizontal plane, is acted upon by a horizontal force P and another force Q, inclined at an angle θ to the vertical. The block ill remain in equilibrium, if the coefficient of friction between it and the surface is:

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(P+Q sin θ)(mg+Q cos θ)

(P cos θ +Q)(mg-Q sin θ)

(P + Q cos θ)(mg +Q sin θ)

(P sin θ-Q)-(mg-Q cos θ)

answer is .

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Detailed Solution

Frictional force = μR = μ(mg+Q cosθ)And horizontal push = P+Q sin θFor equilibrium, we haveμ(mg+Q cos θ) = P+Q sin θμ = P+Q sin θmg+Q cos θ

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