Q.

A block of mass m is lying on a horizontal surface of coefficient of friction μ. A force F is applied to the block at an angle θ with the horizontal. The block will move with a minimum force F if

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

μ=tan ⁡θ

b

μ=cot⁡ θ

c

μ=sin ⁡θ

d

μ=cos⁡ θ

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Refer to diagram, Vertical component of F is F sin θ and the horizontal component is F cos θ. Thus              R+F sin ⁡θ=mg  or   R=mg−F sin⁡ θFrictional force  μR=μ(mg-F sin θ). Also μ(mg-F sin θ)=F cos θor    F=μmg(μ sin⁡θ+cos ⁡θ)         (i)F will be minimum if the denominator is maximum, i.e., if ddθ(μ sin⁡ θ+cos ⁡θ)=0or μcos ⁡θ−sin ⁡θ=0or μ=tan ⁡θ
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon