A block of mass m is lying on a horizontal surface of coefficient of friction μ. A force F is applied to the block at an angle θ with the horizontal. The block will move with a minimum force F if
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a
μ=tan θ
b
μ=cot θ
c
μ=sin θ
d
μ=cos θ
answer is A.
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Detailed Solution
Refer to diagram, Vertical component of F is F sin θ and the horizontal component is F cos θ. Thus R+F sin θ=mg or R=mg−F sin θFrictional force μR=μ(mg-F sin θ). Also μ(mg-F sin θ)=F cos θor F=μmg(μ sinθ+cos θ) (i)F will be minimum if the denominator is maximum, i.e., if ddθ(μ sin θ+cos θ)=0or μcos θ−sin θ=0or μ=tan θ