The block of mass M moving on the friction less horizontal surface, collides with the spring of the spring constant K and compresses it by length L. The maximum momentum of the block after collision is
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a
zero
b
ML2K
c
MK⋅L
d
KL22M
answer is C.
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Detailed Solution
Elastic Energy stored in spring = 12 KL2 here K is force constant, L is length of compression ∴ K.E. of the Block E = 12 KL2 ∴ p2 = 2M⋅E; here p = momentum, m=mass; E = KE ∴ p = 2ME substitute E value p = 2M⋅KL22 p = MK⋅ L