First slide

Work

Question

The block of mass M moving on the friction less horizontal surface, collides with the spring of the spring constant K and compresses it by length L. The maximum momentum of the block after collision is

Moderate

A

zero
B

$\frac{M L^{2}}{K}$
C

$\sqrt{M K} \cdot L$
D

$\frac{K L^{2}}{2 M}$

Solution

Elastic Energy stored in spring = $\frac{1}{2} K L^{2}$
here K is force constant, L is length of compression

$∴$ K.E. of the Block E = $\frac{1}{2} K L^{2}$
$∴ p^{2} = 2 M \cdot E; h e r e p = m o m e n t u m, m = m a s s; E = K E$

$∴ p = \sqrt{2 M E} s u b s t i t u t e E v a l u e p = \sqrt{2 M \cdot \frac{K L^{2}}{2}} p = \sqrt{M K} \cdot L$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App