The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant K and compresses it by length L. The maximum momentum of the block after collision is
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a
Zero
b
ML2K
c
MK L
d
KL22M
answer is C.
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Detailed Solution
When block of mass M collides with the spring its kinetic energy gets converted into elastic potential energy of the spring. From the law of conservation of energy 12Mv2=12KL2 ∴v=KMLWhere v is the velocity of block by which it collides with spring. So, its maximum momentum P=Mv=MKM L=MK LAfter collision the block will rebound with same linear momentum.