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Coefficient of restitution
Question

A block of mass m moving with speed v collides with another block of mass 2m at rest. The lighter block comes to rest after the collision. The coefficient of restitution is

Easy
Solution

\large mv = 2m{v_2} \Rightarrow {v_2} = \frac{v}{2}

\large e = \frac{{{v_2} - {v_1}}}{{{u_1} - {u_2}}} = \left( {\frac{{\frac{v}{2} - 0}}{{v - 0}}} \right) = \frac{1}{2}

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