A block of mass m moving with speed v0 strikes another particle of mass 2m at rest. If collision is head on and the coefficient of restitution e = 1/2, then the loss in kinetic energy will be
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a
12mv02
b
14mv02
c
23mv02
d
34mv02
answer is B.
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Detailed Solution
Loss in K.E.12m1m2m1+m2v1−v221−e212m×2m3mv021−14122m3v0234=mv024