A block of mass m is placed on another block of mass M which itself is lying on a horizontal surface. The coefficient of friction between the block of mass M and horizontal surface is μ1 and that between the two blocks is μ2 . What maximum horizontal force can be applied to the lower block so that the two blocks move without separation?
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answer is 2.
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Detailed Solution
Maximum acceleration of m by friction = their maximum common acceleration μ2mgm=F−μ1(M+m)gM+msolving we get,F=(M+m)(μ2+μ1)g